if the polynomial 6x⁴ 8x³ 5x² ax+b

According to the Rational Root Theorem, which could be a factor of the polynomial f(x) = 6x4 - 21x3 - 4x2 + 24x - 35? p(x) = 2x³ – x² + 3x -1 (c) 3 Product of the roots = αs = 0 (c) 4 (b) A and C have the same sign 2x - 7 According to the Rational Root Theorem, the following are potential roots of … now α = 0 p(2) = 0 Imaginary and complex roots occur only in pairs; so other root is: (2 + i)/2. (a) 12 (c) \(\frac{4}{3}\) (c) at most 2 zeros Answer: (b) c = 0 Question 1. Division Algorithm for polynomials states that, Dividend = _________ x _________ + Remainder. (b) 2 (a) (x – α)(x – s) (d) 4, Answer: (d) 4 If the point (5,0), (0-2) and (3,6) lie on the graph of a polynomial. α² + s² = 25 (d) x2 – 4x + 12, Question 44. (vi) −2+2 −1+3 is an expression having negative integral powers of x. (a) a = 20, b = – 25 The sum of the zeroes of a cubic polynomial is ______, Answer: – \(\frac{coefficient of x²}{coefficient of x³}\). (d) \(\frac{p}{q}\), Answer: (c) \(\frac{- p}{r}\) will mark brainlist, ᴵ ʷᵃˢ ᶠᵘᶜᵏᵉᵈ ʷʰⁱˡᵉ ᴵ ʷᵃˢ ᵈʳᵘⁿᵏ ᵃⁿᵈ ᵗʰᵉʸ ˡᵉᵃᵏᵉᵈ ᵖʰᵒᵗᵒˢ ᵗᵒ ᵗʰᵉ ⁿᵉᵗʷᵒʳᵏ If the polynomial 6x4+8x3+17x2+21x+7 is divided by another polynomial 3x2+4x+1, the remainder comes out to be (ax+b),find a and b - 4127217 (c) k(x² – \(\frac{5}{2}\)x – 41) (a) 0,x³ + 5x + 7 (b) \(\frac { 7 }{ 10 }\) and \(\frac { -7 }{ 10 }\) (b) x, 2x + 3 Write the terms as products using the GCFs. 2. Answer: (a) x² – 4x + 1 (b) 2 (a) \(\frac { 10 }{ 7 }\) and \(\frac { -10 }{ 7 }\) (d) more than 4, Question 41. (b) 49 Students are advised to solve the Polynomials Multiple Choice Questions of Class 10 Maths to know different concepts. (c) k(x³ – x² – 6x) (a) 2 If a is a zero of p(x), then ________ is a factor of p(x). Answer: (b) 2 If 5 is a zero of the quadratic polynomial, x2 – kx – 15 then the value of k is (b) 5 (d) \(\frac { 7 }{ 2 }\), Question 54. If a polynomial p(x) is divided by b – ax; the remainder is the value of p(x) at x = p(- 2) = 0 (d) – 9, Answer: (b) 15 Answer: (c) at most 2 zeros Given that two of the zeroes of the x = \(\frac{b}{a}\), Question 3. (b) cannot both be negative (d) a = – 20, b = – 25, Answer: (d) a = – 20, b = – 25 But what if … 2a + b = 2=>a = 0and b = 2, Question 6. (x - 2) is the other factor. The zeroes of the quadratic polynomial 3x2 – 48 are When we divide x³ + 5x + 7 by x⁴ – 7x² – 6 then quotient and remainder are (respectively): \(\frac{α}{s}\) + \(\frac{s}{α}\) Find a cubic polynomial with the sum, sum of the product of its zeros taken two at a time and the product of its zeros as -2, +5, -3, respectively. (d) a – b – 1, Question 42. Let, α, s, v be the zeroes of x³ + 4x² + x- 6 such that product of two of the zeroes is 6. If α, s, v are the zeros of the polynomial 2x³ – x² + 3x -1, find the value of (αsv) + (αs + sv + vα). A quadratic equation is a second degree polynomial having the general form ax^2 + bx + c = 0, where a, b, and c... Read More. => α²+s²-2αs = 4 We have, p(x)=x^4–2x^3+3x^2-ax+b By remainder theorem, when p(x) is divided by (x-1) and (x+1) , the remainders are equal to p(1) and p(-1) respectively. (a) (\(\frac { 5 }{ 2 }\), 0) (d) – 10, Answer: (d) – 10 (d) both equal, Answer: (b) one positive and one negative, Question 14. The first 2 terms has a GCF of 5x². (c) a – b + 1 (a) \(\frac{- c}{a}\) if the polynomial 6x 4 +8x 3-5x 2 +ax+b is exactly divisible by the polynomial 2x 2-5, then find the values of a and b. 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(b) x² + qx + p (a)y + 1 k = -12, Question 10. Darragh has a golden Eagle coin in his collection with a mass of 13.551 g. An uncirculated golden Eagle coin has a mass of 13.714 . (b) R(x) = 0 or deg R(x) > deg D(x) (c) – 1 (a) 3 q = ±√2, Question 22. Solving a polynomial equation p(x) = 0 2. (b) both negative ᵂᵃⁱᵗⁱⁿᵍ ᶠᵒʳ ʸᵒᵘ: chatt-sex.online. ( make in simple present tense.) \(\frac{Coefficient of x²}{Coefficient of x³}\), Question 36. (c) – 3 The zeroes of the quadratic polynomial x2 + px + p, p ≠ 0 are required polynomial is x³ + 2x² + 5x + 3, Question 30. other two zeroes is i) Rationalizing 1/2i, it is = -i/2. 5x⁴+7x¹, 8y³-2Y²+15, 25x²-0, 16x⁵+ 8x³-2x²-4x+7, etc. When f x( ) is divided by (x−2) the remainder is R. When f x( ) is divided by (x−3) the remainder is 6R. If a polynomial p(y) is divided by y + 2, then which of the following can be the remainder: (c) x³ + 2x² + 5x + 3 (c) both positive (b) 22 (d) \(\frac{a}{b}\), Answer: (b) \(\frac{b}{a}\) Write a polynomial with zeros 1, – 1 and 1. sum of zeroes = (p – q) + p + (p + q) Question 20. (a) 12 (d) more than 3, Question 46. Students can access the NCERT MCQ Questions for Class 10 Maths Chapter 2 Polynomials with Answers Pdf free download aids in your exam preparation and you can get a good hold of the chapter. b – ax = 0 – b/a = – 2 (d) \(\frac{5}{3}\), Answer: (a) \(\frac{2}{3}\) (d) a = \(\frac{b}{c}\), Answer: (a) ab = c (a) x2 + 4x + 12 1 – 2x is a factor of p(x), Question 5. If -2 is a zero of p(x) = (ax³ + bx² + x – 6) and p(x) leaves a remainder 4 when divided by (x – 2), then the values of a and b are (respectively): Question 38. (a) x² + px + q k(x² – \(\frac{5}{2}\)x + 41), Question 15. Since the graph meets X-axis at x = 0 (a) \(\frac { -3 }{ 2 }\) and – 1 This is pretty simple. are examples of polynomials. (d) k(x- s). (d) both cannot be negative, Question 56. sum of the roots = – \(\frac{coefficient of x}{coefficient of x²}\) = \(\frac{b}{c}\), Question 25. Me to sharif hu...Tum log hi mele ko pgl bole...mele ko bt hi nhi klni... :(​, cmk-azka-wpa only sex girls can join who want to learn sex come fast only girls u only on Ur camera I not on the camera​, सिद्ध कीजिया कि 4-√5 एक अपरिमेय संख्या है यदि √5 अपरिमेय संख्या हो​. further = αs + sv + vα = \(\frac{c}{a}\) (d) k(x³ – 6x), Answer: (c) k(x³ – x² – 6x) α + s = – 7 If the polynomials ax³ + 4x² + 3x – 4 and x³ – 4x + a, leave the same remainder when divided by (x – 3), then value of a is : (b) 3 (d) 4x² – x + 1. (b) 4x³ + 5x² – 3x + 7 Finding roots of a polynomial equation p(x) = 0 3. (b) k(x² – \(\frac{5}{2}\)x + 41) a = – 1, Question 4. (a) cannot both be positive (b) – 5, – 6 If a, s are the zeroes of x² – 8x + λ, such (d) qx² + px +1, Answer: (d) qx² + px +1 zeros are 1, – 1 and 1. (a) 5 If a and ß are the zeroes of the polynomial 5x2 – 7x + 2, then sum of their reciprocals is: Hence, value of k is 1 (a) 8 (a) 0 (b) \(\frac{3}{2}\) Answer: (b) 0 The sum and product of the zeroes of the polynomial x2-6x+8 are respectively αs + sv + vα + αsv = \(\frac{3}{2}\) + \(\frac{1}{2}\) = 2, Question 21. if the polynomial 6x^4 + 8x^3 - 5x^2 +ax + b is exactly divisble by the polynomial 2x^2-5, then find thr value of a And b. thuada means bhajii.....koi chakar nhi brother.tuci Jo bolna bolo​, Bheja is working tb jb bheja is howing...xD​, The area under standard normal curve between the lines z=2.58​, please answer correctly no spam please thank you! If one zero of the quadratic polynomial x2 + 3x + k is 2, then the value of k is (c) ab = \(\frac{c}{2}\) ? (b) a = 0,b = – 2 Learn vocabulary, terms, and more with flashcards, games, and other study tools. αs = λ sum of the squares of the zeroes of the polynomial p(x) = x² + 7x – k is 25, find k. - eanswers-in.com (b) 15 If α, s are the roots of cx² – bx + a = 0 (c 0), then α + s is: If α, s are the zeroes of x² – lx + m, then If x101 + 1001 is divided by x + 1, then remainder is: α = \(\frac{1}{3}\) (a) b = 0 (c) 4 Make sure you aren’t confused by the terminology. (a) 6 Answer: Value of k is 1 . (a) A and B have the same sign => v = 6, Question 12. (b) x2 – 4x – 12 Factor it out. b) Find the value of A and the value B. When p(y) is divided by y + 2, then the degree of remainder < deg of (y + 2), Question 2. a) Show clearly that B A− = 14 . p(x) is a multiple of 1 – 2x. (a) 2 (x−r) is a factor if and only if r is a root. If P(x) and D(r) are any two polynomials such that D(x) ≠ 0, there exists unique polynomial Q(x) and R(x) such that, P(x) = D(x). (c) -7 and 10 For example, x 2 y 5 is a term in the polynomial, the degree of the term is 2+5, which is equal to 7. If one of the zeroes of the cubic polynomial x3 + ax2 + bx + c is -1, then the product of the (b) x² + 4x – 1 (d) 0, Answer: (a) 2 The graph of the polynomial f(x) = 2x – 5 intersects the x – axis at Answer. So from the above data, f(-1) = 6 and f(1) = 0. (b) both cannot be positive (c) not defined if α, s are the zeros of p(x), then (x – α)(x – s) is a factor of p(x). MCQ Questions for Class 8 Maths with Answers were prepared based on the latest exam pattern. (b) x³ – x² + x + 1 k=1. (b) -10 Learn vocabulary, terms, and more with flashcards, games, and other study tools. thanks! (c)\(\frac{- 1}{2}\) Students can download the Polynomials Class 10 MCQs Questions with Answers from here and test their problem-solving skills. (ix) 𝑥 2 2 −2 2= 𝑥 2 2 −2 −2 required polynomial = k(x – 2)(x – 0)(x – 3) (b) a = 5, b = -1 (d) 15, Answer: (d) 15 (d) 5, – 6, Question 50. (b) (x + α) (x + s) You can specify conditions of storing and accessing cookies in your browser, PLZZ check the attachment for answer.... Hope it is help full. The number of polynomials having zeroes as 4 and 7 is p(- 1) = (-1101) + 1001 = 1000. (d) 7 and -10, Question 49. (a) k(x² + \(\frac{5}{2}\)x – 41) Substituting it, 3(-1)^4-a(-1)^3+2a(-1)^2-(-1)-b = 6 i.e. α + s = – \(\frac{5}{2}\) 2. (d) are always equal, Question 51. αs = 61 (d) – 2. 3. => Sum of the roots = α + 0 + 0 => 64 — 4λ = 4 If the polynomial 6x 4 + 8x 3 - 5x 2 + ax +b is exactly divisible by the polynomial 2x 2 - 5 then find the value of a and b Asked by | 28th May, 2012, 12:15: PM Expert Answer: The zeroes of the quadratic polynomial x2 + 1750x + 175000 are So we can factorize the polynomial using grouping terms, First rearranging in standard form in decreasing order of degrees of x. Grouping two terms together, we get, Now taking common from first two and 5 from last two , we have, Now, taking (x+2) common, we have, Thus, We can factorize the polynomial using method of grouping terms. (a) R(x) = 0 and deg R(x) > deg Q(x) (a) b – a + 1 2. The graph of a polynomial is as shown, find the polynomial ii) So {x - (2 - i)/2} and {x - (2 + i)/2} are two factors of the given polynomial. If – 2 is a zero => (c) one positive and one negative α + s = 8, => (α + s)² – 4as = 4 (b) 6 Factoring a polynomial function p(x)There’s a factor for every root, and vice versa. Solving quadratics by factorizing (link to previous post) usually works just fine. 1. (b)2y + 3 = 60 (c) both positive If one zero of 3x² – 8x + 2k + 1 is seven times the other, find k. Update: Which polynomial, when added to the polynomial 5x2–3x–9, is equivalent to:18 (5x² - 3x - 9) + (- 5x² + 3x + 27) = 18 (d)y – 1, Answer: (c) 5 Compare above with given factored form, we get. If 2 is a zero of p(x) = x² + 3x + k, find k: Question 34. (a) both equal - 1153070 (c) 2 (b) 6 and 8 (a) 2b (b) \(\frac{p}{r}\) (b) (\(\frac { -5 }{ 2 }\), 0) High School Math Solutions – Quadratic Equations Calculator, Part 2. (a) 1 polynomial ax³ + bx² + cx + d is zero, then the product of the other two zeroes is: Check the below NCERT MCQ Questions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities with Answers Pdf free download. (b) \(\frac { 7 }{ 5 }\) Which is the completely factored form of his polynomial? 4. polynomial. (b) 0 Example: 2x 3 −x 2 −7x+2. (c) \(\frac{- b}{a}\) A quadratic equation can have ________ two roots, (exactly/atleast/atmost). (a) \(\frac{l² – 2m}{m}\) Also, the highest power of x is 2, so, it is a polynomial of degree 2. (b) at least 3 (d) – 12, Answer: (c) 2 If the polynomial x 4 – 6x 3 + 16x 2 – 25x + 10 is divided by another polynomial x 2 - 2x + k, the remainder comes out to be x + a, find ‘k’ and ‘a’. CBSE > Class 10 > Mathematics 1 answers; Don 5 1 year, 7 months ago. Finding zeroes of a polynomial function p(x) 4. (a) both negative Nothing factors again. (a) 10 If x = 2 and x = 3 are zeros of the quadratic polynomial x2 + ax + b, the values of a and b respectively are : The value of b, for which 2x³ + 9x² – x – b is exactly divisible by 2x + 3 is: Q(x) + R(x) where : Answer: (d) More than 3. Let, α, s, v be the roots =α + s + v = a when 2x³ + 9x² – x – b is divided by 2x + 3, remainder is – b + 15, Question 28. (a) a = 20, b = – 25 (b) a = 4, b = – 5 (c) a = 20, b = 5 (d) a = – 20, b = – 25. 3. If α, s are the zeroes of x² + px + q, then a polynomial having zeroes \(\frac{1}{α}\) and \(\frac{1}{s}\) is, (viii) Clearly, −3 5 is a constant polynomial of degree 0. 👍 Correct answer to the question: Soapy left soapy left his bench. (a) -15 αs = \(\frac{k}{2}\) (5x² + 3)(x - 2) are the factors. Practicing the MCQ Questions on Polynomials Class 10 with answers will boost your confidence thereby helping you score well in the exam. Start studying Algebra Chapter 8.1 - 8.4 Test Review - Polynomials. (d) – 4, Question 45. α + s = \(\frac{5}{2}\) (d) 1000, Answer: (d) 1000 (a) 2 Question 37. polynomial, x³ + px² + rx + s are 0, then third zero (α + s)² – αs = \(\frac{21}{4}\) (c) 1,x⁴ – 7x²-6 The polynomial that gives a quotient of (3x² + 2x + 4) and a remainder of 19 when divided by (2x – 3) is 6x³ – 5x² + 2x + 7 since 6x³ – 5x² + 2x + 7 divided by 2x – 3 is 3x² + 2x + 4. Factor 8x³-4x²-16x by GCF. \(\frac{25}{4}\) – \(\frac{k}{2}\) = \(\frac{21}{4}\) (b) -2 (d) 8, Answer: (a) 25 -3x^3+7x^2+5x+2 2. subtract and simplify 6sqrt 48-7sqrt 3 3. find … It is further given that (x+3) is factor of f x( ). (c) \(\frac{1}{2}\) (αs + sv + vα + αsv )² = 4, Question 33. (d) R(x) = 0 or deg R(x) < deg D(x), Answer: (b) R(x) = 0 or deg R(x) > deg D(x) 5. (c) \(\frac{- p}{r}\) Step-by-step explanation: Given the polynomial . Type the equation in standard form ax^2 +bx+c=0 Solution: 4, only solution The equation is =0 2. (c) – 5, 6 Question 7. α + 7α = 8α = \(\frac{8}{3}\) (d) l² – 2m, Answer: (a) \(\frac{l² – 2m}{m}\) (a) a (b) 3 A quadratic polynomial has : By division algorithm, we have It is given that f(a) = x 4 – 6x 3 + 16x 2 – 25x + 10, when divided by x 2 – 2x + k leaves x + a as remainder. (c) k(x – α) (d) a = 0, b = 0, Answer: (c) a = 0, b = 2 Given that one of the zeroes of the (a) x³ + x² + x + 1 Explore numerous MCQ Questions of Polynomials Class 10 with answers provided with detailed solutions by looking below. We can say that the polynomial in the variable a. (c) 1490 Question 24. If the polynomial 6x 4 + 8x 3 - 5x 2 + ax + +b is exactly divisible by the polynomial 2x 2 - 5 , then find the value of a & b. pls do it urgently. If α, s and v are the zeroes of the polynomial 2x³ – x² + 3x – 1, find the value of => (as + sv + va + asv )² If α and s are two zeros of the polynomial p(x), then which of the following is a factor of p(x): = \(\frac{c}{a}\) = 0, Question 8. (c) (\(\frac { -5 }{ 2 }\), \(\frac { 5 }{ 2 }\)) = 3 => Zero of p(x) is ‘O’ => Correct option is (b). p(x) = ax³ + 4x² + 3x – 4 0 + sv + 0 = \(\frac{c}{a}\) If the zeroes of the quadratic polynomial Ax2 + Bx + C, C # 0 are equal, then Identify and factor the GCF out of every group. Quadratic Polynomial A polynomial of degree two, is called quadratic polynomial. Find the third zero. If p(x) = 2x⁴ – ax³ + 4x² + 2x + 1 is a. multiple of 1 – 2x, then find the value of a : (a) 25 The zeroes of the quadratic polynomial x2 + kx + k, k ≠ 0, (d) k(- x² + \(\frac{5}{2}\)x + 41), Answer: (b) k(x² – \(\frac{5}{2}\)x + 41) = 3p (c) a = 20, b = 5 (c) 4x² + x – 1 Simplify the expression (x³+4+6x⁴)-(3-6x²-3x³-3x⁴) 24x²-2x-1. (a)a = 2,b = 2 1. if the polynomial 6x^4 + 8x^3 - 5x^2 + ax + b is exactly divisible by 2x^2 - 5, then find the values of a and b. (d) 1, Answer: (a) 6 Two zeroes are zero, let third zero = α Share with your friends. (c) x³ – x² – x – 1 (c) both unequal (d) ±√2, Answer: (d) ±√2 n – number of polynomials can have zeroes -1 and -5. (a) at least 2 zeros (b) 4 how do i solve these?? αs = m, Question 9. (b) \(\frac{1}{2}\) If α, s are the zeroes of p(x) = 2x² – 5x + 7, write a polynomial with zeroes 2α+3s and 3α+2s. (d) both equal, 1. (c) B and C have the same sign (c) \(\frac { -3 }{ 2 }\) and 1 (a) 3 c/a = 5 (c) 60 (d) More than 3. Generally, any linear polynomial in variable x with real coefficients is of the form f (x) = ax + b, where a and b are real numbers and a ≠ 0. (d) – 12, Answer: (d) – 12 5x²(x - 2) + 3(x - 2) Now put 5x² and + 3 together as one factor. (b) 0 This site is using cookies under cookie policy. α + s = – p (b) \(\frac{5}{2}\) (b) \(\frac{b}{a}\) Which of the following Linear Graphs has no zero? ... Identify the degree of each term of the polynomial and the degree of the polynomial. Terdapat juga beberapa syarat sehingga sebuah persamaan bisa disebut sebagai ‘polinomial’, diantaranya ialah sebagai berikut: 1. Then which of the following is a zero of the polynomial? If the zeros of the polynomial x³ – 3x² + x +1 are p – q,p and p + q. Write the zero of the polynomial p(x), whose graph is given : (c) \(\frac{c}{a}\) (c) 2 Share 33. the given polynomial is divisible by . (c) 1 Start studying Polynomial Division. The number of polynomials having zeroes – 1 and – 5 is : α + s = l Find a and b so that the polynomial 6x⁴ + 8x³ – 5x² + ax + b is exactly divisible by 2x² – 5. 5x³ - 10x² + 3x - 6. Use MCQ Questions for Class 10 Maths with Answers during preparation and score maximum marks in the exam. (c) 2 (d) -2, Question 53. αsv = – d/a = \(\frac{1}{2}\) =>4 + 6 + k = 0 Question 23. If a and b are the exponents of the multiple variables in a term, then the degree of a term in the polynomial expression is given as a+b. (c) 1 If one zero of a polynomial p(x) = ax² + bx + c(a ≠ 0) is zero, then, which of the following is correct: (a) \(\frac{2}{3}\) let α,s be the zeroes The polynomial 4 9x Ax Bx3 2+ + + , where A and B are constants, is denoted by f x( ). (d) -5, Question 55. All of these arethe same: 1. Sum and the product of zeroes of the polynomial x2 +7x +10 is (c) 5 we have to find the value of k in factored form. (c) are always unequal (c) 1 = k(x³ – x² – 6x), Question 32. (d) x², 4x – 9, Answer: (a) 0,x³ + 5x + 7 (p – q) p + p(p + q) + (p – q)(p + q)=1 Find the value of q. Divide the given polynomial by 2×2 – 5 get the remainder as (20 + a)x + (b + 25) which should be zero, Question 14. A quadratic polynomial has atmost two zeroes. p(x) = x² + 7x – k If a polynomial p(x) does not touch _______ axis, then it has no zeroes. Clear all the fundamentals and prepare thoroughly for the exam taking help from Class 10 Maths Chapter 2 Polynomials Objective Questions. if the polynomial 6x^4 + 8x^3 - 5x^2 +ax + b is exactly divisble by the polynomial 2x^2-5, then find thr value of a And b. α² + s² +αs = \(\frac{21}{4}\) (a) k(x² – x – 6) that α – s = 2, then X = Find the product (4x-1)(6x+1) (c) 5 Using basics of remainder theorem, remainder of f(x) when divided with (x-a) will be f(a). If the polynomial 6x4 + 8x3 + 5x2 + ax + b is exactly divisible by the polynomial 2x2 -5, the find the values of a and b. ... 5x² (3-2x) … (d) \(\frac{b}{c}\), Answer: (d) \(\frac{b}{c}\) (b) a = 4, b = – 5 (d) both equal, Question 47. q(x) = x³ – 4x + a (d) (\(\frac { 5 }{ 2 }\), \(\frac { -5 }{ 2 }\)), Question 39. (b) – 1 (a) 1 (d) at most 3, Question 43. (c) deg R(x) < deg Q(x) (a) 10 (b) b – a – 1 (b) \(\frac{l² + 2m}{m}\) α s v = 6, (α² + s) – 2αs = 25 (d) exactly 1 zero. If sum of the two zeroes of a cubic polynomial x³ – ax² + bx – c, is zero, then which of the following is true: Group the terms that have common factors. (a) \(\frac{- b}{a}\) (a) both positive division algorithm, Question 26. (c) \(\frac{1}{2}\) p(3) = q(3) 2. GCF = 4x 4x (2x²-1x-4) or 4x (2x²-x-4) What are the steps to Factoring by Grouping? (a) a = -7, b = -1 αs + sv + vα + αsv = \(\frac{3}{2}\) + \(\frac{1}{2}\) = 2 ab = c, Question 16. = x³ – x² – x + 1, Question 31. (d) A and C have opposite signs, Question 40. let ,α = 0 (b) 2 Find the GCF of all the terms in the polynomial. v = a now v is a zero p(x) is divided by x + 1 (b) one positive and one negative (c) px² + qx + 1 Find the quadratic polynomial whose zeros are 2 and -6 Variabel tidak boleh mempunyai pangkat pecahan atau negatif. 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